Find P(A or B or C) for the given probabilities. P(A=0.38, P(B)=0.28, P(C)=0.11 P(A and B)= 0.11, P(A and C)=0.02, P(B and C)=0.07 P(A and B and C)= 0.01

Accepted Solution

Attached is a ven diagram which may be helpful for this problem.

Each number is a probability. The sum of all the numbers is P(A or B or C).

To find these numbers, start in the middle and work your way out.

The middle is P(A and B and C), which is 1. Then simply subtract this from each of the larger intersections. 

Finally the parts not in an intersection. Only in A not B not C. You just subtract the numbers in A from P(A).  ---> 38 - 10 -1 - 1 = 26

Add them up and you get 58.

P(A or B or C) = 0.58