MATH SOLVE

4 months ago

Q:
# Luiza João tem juntos R$123 se Luiz tivesse a mais metade da quantia que tem mais um real teria dobro de João quanto tem cada um

Accepted Solution

A:

Answer:A=25B=98Step-by-step explanation:You can see it as a 2-eq system.Call A Joao's money and B Luiz's money. The sum is $123:A + B = 123As the half of Luiz's money + 1 is the double of Joao's money, we could represent this as:(B/2) + 1 = 2A [this is what the last sentence says]We can get the A value by dividing both sides by 2:[(B/2) + 1]/2 = 2A / 2B/4 + 1/2 = AThen, replacing this A value on our first equation:B/4 + 1/2 + B = 123B/4 + 4B/4 = 123 - 1/2(5/4)B = 122.5Multiplying by (4/5) [or dividing by 5/4] to eliminate this 5/4:(5/4) B * (4/5) = 122.5(4/5)B = 98Then we find A:A = B/4 + 1/2 = 24.5 + 0.5 = 25A=25