Q:

Use the graph below to answer the question that follows: cosine graph with points at 0, negative 1 and pi over 3, 0 and pi, 3 and 5 pi over 3, 0 and 2 pi, negative 1 What are the amplitude, period, and midline of the function?Amplitude: 4; period: π; midline: y = 2 Amplitude: 2; period: 2π; midline: y = 1 Amplitude: 4; period: 2π; midline: y = 1 Amplitude: 2; period: π; midline: y = 2

Accepted Solution

A:
For this case the amplitude is given by:
 A = (l-1l + 3) / 2
 A = 4/2
 A = 2
 The middle line is given by:
 y = 1
 The period of the function is given by:
 T = l x2 - x1 l
 T = l 0 - 2pi l
 T = l - 2pi l
 T = 2pi
 Answer:
 Amplitude: 2; period: 2π; midline: y = 1