MATH SOLVE

4 months ago

Q:
# Use the graph below to answer the question that follows: cosine graph with points at 0, negative 1 and pi over 3, 0 and pi, 3 and 5 pi over 3, 0 and 2 pi, negative 1 What are the amplitude, period, and midline of the function?Amplitude: 4; period: π; midline: y = 2 Amplitude: 2; period: 2π; midline: y = 1 Amplitude: 4; period: 2π; midline: y = 1 Amplitude: 2; period: π; midline: y = 2

Accepted Solution

A:

For this case the amplitude is given by:

A = (l-1l + 3) / 2

A = 4/2

A = 2

The middle line is given by:

y = 1

The period of the function is given by:

T = l x2 - x1 l

T = l 0 - 2pi l

T = l - 2pi l

T = 2pi

Answer:

Amplitude: 2; period: 2π; midline: y = 1

A = (l-1l + 3) / 2

A = 4/2

A = 2

The middle line is given by:

y = 1

The period of the function is given by:

T = l x2 - x1 l

T = l 0 - 2pi l

T = l - 2pi l

T = 2pi

Answer:

Amplitude: 2; period: 2π; midline: y = 1